本文讲述用PHP以及js查询字符串中子字符串所有出现位置
JS中indexOf()方法可返回某个指定的字符串值在字符串中首次出现的位置。运用第二个参数，循环调用就能获取到子串出现的所有位置。
/**
* 查询字符串中子字符串出现位置
* @param str
* @param substr
* @return {Array}
*/
function search_substr_pos(str, substr) {
var _search_pos = str.indexOf(substr), _arr_positions = [];
while (_search_pos > -1) {
_arr_positions.push(_search_pos);
_search_pos = str.indexOf(substr, _search_pos + 1);
}
return _arr_positions;
}
var str = "look at me,is there anything can prove that I am a good guy ?";
var $_pos_substr = search_substr_pos(str, 'e');//子串位置
var $_times_substr = $_pos_substr.length;//出现次数
console.log($_pos_substr); // [ 9, 16, 18, 37 ]
console.log($_times_substr); // 4
同理，PHP中使用strpos()方法
/**
* 查询字符串中子字符串出现位置
* @param $str
* @param $substr
* @return array
*/
function search_substr_pos($str, $substr)
{
$_search_pos = strpos($str, $substr);
$_arr_positions = array();
while ($_search_pos > -1) {
$_arr_positions[] = $_search_pos;
$_search_pos = strpos($str, $substr, $_search_pos + 1);
}
return $_arr_positions;
}
$str = "look at me,is there anything can prove that I am a good guy ?";
$_pos_substr = search_substr_pos($str, 'e');//子串位置
$_times_substr = count($_pos_substr);//出现次数
print_r($_pos_substr); // Array ( [0] => 9 [1] => 16 [2] => 18 [3] => 37 )
print_r($_times_substr); // 4
